document.write( "Question 798504: how many liters of a 50% acid solution must be mixed with a 20% acid solution to get 270 liters of a 40% acid solution \n" ); document.write( "
Algebra.Com's Answer #482254 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "acid I 50.00% ---------------- x liters
\n" ); document.write( "Acid II 20.00% ------ 270 - x liters
\n" ); document.write( "Mixture 40.00% ---------------- 270
\n" ); document.write( "Total 270 liters
\n" ); document.write( "50.00% x + 20.00% ( 270 - x ) = 40.00% * 270
\n" ); document.write( "50 x + 20 ( 270 - x ) = 10800
\n" ); document.write( "50 x + 5400 - 20 x = 10800
\n" ); document.write( "50 x - 20 x = 10800 - -5400
\n" ); document.write( "30 x = 5400
\n" ); document.write( "/ 30
\n" ); document.write( " x = 180 liters 50.00% acid I
\n" ); document.write( " 90 liters 20.00% Acid II
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\n" ); document.write( "m.ananth@hotmail.ca
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