document.write( "Question 798525: A motorist undertakes a journey to a point and travels at an average speed of 50km/h. His average speed for the return journey is 60km/h and he completes it in 3 hours less than it took him to reach his destination. How long did the forward journey take? \n" ); document.write( "
Algebra.Com's Answer #482252 by mananth(16946)\"\" \"About 
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let him take x hours to go there\r
\n" ); document.write( "\n" ); document.write( "distance = 50x\r
\n" ); document.write( "\n" ); document.write( "return he takes x-3 hours
\n" ); document.write( "at 60 km/h\r
\n" ); document.write( "\n" ); document.write( "distance = (x-3)*60\r
\n" ); document.write( "\n" ); document.write( "distance is same\r
\n" ); document.write( "\n" ); document.write( "(x-3)*60=50x\r
\n" ); document.write( "\n" ); document.write( "60x-180=50x\r
\n" ); document.write( "\n" ); document.write( "10x=180\r
\n" ); document.write( "\n" ); document.write( "x=18 hours
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