document.write( "Question 67822: An orange drink claims that it contains 10% orange juice. How much pure orange juice would need to be added to 5 quarts of the drink to make a mixture of 40% orange juice.\r
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Algebra.Com's Answer #48225 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x=amount of pure orange juice that needs to be added\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure orange juice in the 10% mixture (0.1)(5) plus the amount of pure orange juice added (x) has to equal the amount of pure orange juice in the final mixture (0.4)(5+x). Our equation to solve:\r
\n" ); document.write( "\n" ); document.write( "(0.1)(5)+x=(0.4)(5+x) clear parens\r
\n" ); document.write( "\n" ); document.write( "0.5+x=2+0.4x subtract 0.4x and 0.5 from both sides\r
\n" ); document.write( "\n" ); document.write( "0.5-0.5+x-0.4x=2-0.5+0.4x-0.4x collect like terms\r
\n" ); document.write( "\n" ); document.write( "0.6x=1.5\r
\n" ); document.write( "\n" ); document.write( "x=2.5 gal-------------------------ans\r
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\n" ); document.write( "substitute x=2.5 into original equation
\n" ); document.write( "(0.1)(5)+2.5=.4(7.5)
\n" ); document.write( "3=3\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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