document.write( "Question 798486: The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width? \n" ); document.write( "
Algebra.Com's Answer #482241 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width?\r
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\n" ); document.write( "\n" ); document.write( "Let width be W\r
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\n" ); document.write( "\n" ); document.write( "Then length = 5W\r
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\n" ); document.write( "\n" ); document.write( "Therefore, \"2%28W+%2B+5W%29+%3C=+96\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28W+%2B+5W%29+%3C=+2%2848%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+%2B+5W+%3C=+48\"\r
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\n" ); document.write( "\n" ); document.write( "\"6W+%3C=+48\"\r
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\n" ); document.write( "\n" ); document.write( "Width, or \"W+%3C=+48%2F6\", or \"W+%3C=+8\"\r
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\n" ); document.write( "\n" ); document.write( "Greatest possible width: \"highlight_green%288%29\" cm\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!! \r
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\n" ); document.write( "\n" ); document.write( "Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com. Further help is available, online or in-person, for a fee, obviously. \r
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