document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=798486>Question 798486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482236 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = 5w<BR>\n" );
document.write( "width = w<BR>\n" );
document.write( "p = 96\r<BR>\n" );
document.write( "\n" );
document.write( "p = 2w + 2L<BR>\n" );
document.write( "2w + 2(w + 5) = 96<BR>\n" );
document.write( "2w + 2w + 10 = 96<BR>\n" );
document.write( "4w + 10 - 10 = 96 - 10<BR>\n" );
document.write( "4w = 86<BR>\n" );
document.write( "4w/4 = 86/4<BR>\n" );
document.write( "w = 21.5\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "2(21.5) + 2(21.5 + 5( = 96<BR>\n" );
document.write( "43 + 2(26.5) = 96<BR>\n" );
document.write( "43 + 53 = 96<BR>\n" );
document.write( "96 = 96 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );