document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=798465>Question 798465</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bob is one third the age of his father. In 12 years he will be half the age of his father. How old are each now? Must use x as a variable in the equation. There will be an x on both sides of the = sign. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482230 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If Bob is x years father is 3x\r<BR>\n" );
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document.write( "12 years hence\r<BR>\n" );
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document.write( "bob = x+12<BR>\n" );
document.write( "father = 3x+12\r<BR>\n" );
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document.write( "(x+12)=1/2(3x+12)\r<BR>\n" );
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document.write( "2(x+12)=3x+12\r<BR>\n" );
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document.write( "2x+24=3x+12\r<BR>\n" );
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document.write( "3x-2x=24-12<BR>\n" );
document.write( "x=12 bob's age\r<BR>\n" );
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document.write( "father's age = 36  </SPAN>\n" );
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