document.write( "Question 798403: A cylinder has a volume of 20 pi inches ^3. The base and top are made of aluminium that costs $4 per sq inch. The sides are made from rolled steel at a cost of $3.2 per sq inch.\r
\n" ); document.write( "\n" ); document.write( "What is the height of the cheapest container?\r
\n" ); document.write( "\n" ); document.write( "So far: V = pi r^2 h therefore 20pi=pi r^2 h...... therefore h = 20pi/pi r^2
\n" ); document.write( "h=20/r^2 \r
\n" ); document.write( "\n" ); document.write( "Cost= (lid cost)+(base cost)+(side cost)
\n" ); document.write( "Therefore Cost = 4(pi r^2) + 4(pi r^2) + 3.2(2pi r h)
\n" ); document.write( " = 4(pi r^2) + 4(pi r^2) + 3.2(2pi r)(20/r^2) subs h\r
\n" ); document.write( "\n" ); document.write( " = 8(pi r^2) + 128pi/r \r
\n" ); document.write( "\n" ); document.write( "C' therefore = 16pi r - 128pi/r^2\r
\n" ); document.write( "\n" ); document.write( "now I'm stuck, I feel I should multiply top and bottom by r^2 but I cannot see why
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Algebra.Com's Answer #482183 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
You seem to be going in the right direction.
\n" ); document.write( "I'll push you the last fraction of an inch.
\n" ); document.write( "For minimum cost, you want C'=0, which means
\n" ); document.write( "\"16pi%2Ar%5E2-128pi%2Fr=0\" --> \"16pir%5E2=128pi%2Fr\" --> \"16r%5E3=128\" --> {{r^3=128/16}}} --> \"r%5E3=8\" --> \"r=2\"
\n" ); document.write( "So \"h=20%2Fr%5E2=20%2F2%5E2=20%2F4=highlight%285%29\"
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