document.write( "Question 798372: solve:\r
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document.write( "solutions of three equations in three variables:\r
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document.write( "2x+y-z=1
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document.write( "x+2y+2z=2
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document.write( "4x+5y+3z=3\r
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document.write( "PLEASE SHOW WORK!!! (IVE ASKED IN PREVIOUS QUESTIONS TO SHOW WORK AND NO ONE HAS DONE SO .. I JUST NEED TO UNDERSTAND HOW TO DO THIS!) \n" );
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Algebra.Com's Answer #482164 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! solve: \n" ); document.write( "solutions of three equations in three variables: \n" ); document.write( "2x+y-z=1 \n" ); document.write( "x+2y+2z=2 \n" ); document.write( "4x+5y+3z=3 \n" ); document.write( "------------ \n" ); document.write( "Pick a variable to eliminate \n" ); document.write( "z first. \n" ); document.write( "4x+2y-2z =2 Eqn 1 times 2 \n" ); document.write( "x+2y+2z = 2 Eqn 2 \n" ); document.write( "----------------------- Add \n" ); document.write( "5x + 4y = 4 Eqn A \n" ); document.write( "---- \n" ); document.write( "6x+3y-3z=3 Eqn 1 times 3 \n" ); document.write( "4x+5y+3z=3 Eqn 3 \n" ); document.write( "-------------------------- Add \n" ); document.write( "10x + 8y = 6 Eqn B \n" ); document.write( "------- \n" ); document.write( "Now you have 2 eqns in 2 variables. \n" ); document.write( "The next step is to eliminate x or y. \n" ); document.write( "5x + 4y = 4 Eqn A \n" ); document.write( "5x + 4y = 3 Eqn B times 1/2 \n" ); document.write( "------ \n" ); document.write( "It's obvious that the system is inconsistent. \n" ); document.write( "--> no unique solution\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |