document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=798298>Question 798298</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The height of the cone is 6 cm. The angle at the vertex of its axial section is  . Find the surface area of the cone. thank you so much for your response </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482131 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The height of the cone is 6 cm. The angle at the vertex of its axial section is  . Find the surface area of the cone.<BR>\n" );
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document.write( "2A = angle<BR>\n" );
document.write( "Slant height = 6/cos(A) = 6sec(A)<BR>\n" );
document.write( "Lateral area = pi*SH = 6pi*sec(A)<BR>\n" );
document.write( "Area of base = pi*r^2 = 9*pi<BR>\n" );
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