document.write( "Question 764950: if 1st 44 positive integers form a no. N as N=12345678.........424344 and N is divided by 45, then what is the remainder? \n" ); document.write( "
Algebra.Com's Answer #482112 by 9876(1)\"\" \"About 
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The answer is 9 not the 4 as solved by MathLover1(7369).I guanrentee This!\r
\n" ); document.write( "\n" ); document.write( "The number on dividing by 5 leaves remainder 4.\r
\n" ); document.write( "\n" ); document.write( "Digitsum of Numbers (1234......424344)-->
\n" ); document.write( "The number are from 0 to 9 (Sum of digits 45)
\n" ); document.write( "then 10 to 19 (Digit sum 45+1x10 = 55)
\n" ); document.write( "then 20 to 29 (Digit sum 45+2x10 = 65)
\n" ); document.write( "then 30 to 39 (Digit sum 45+3x10 = 75) and
\n" ); document.write( "then 40 to 44 (digit sum (10+4x5 = 30)
\n" ); document.write( "therefore total digit sum come out to be (45+55+65+75+30 = 270)
\n" ); document.write( "This is divisible by 9.\r
\n" ); document.write( "\n" ); document.write( "When the given number is divided by 5 it leaves a remainder 4. So the number is of the form 5A + 4.
\n" ); document.write( "When divided by 9 it leaves a remainder 0. Hence of the form 9B+0.\r
\n" ); document.write( "\n" ); document.write( "Equate both the equations 5A+4=9B.
\n" ); document.write( "Put A= 1 and B= 1 we get 9 which is the remainder.\r
\n" ); document.write( "\n" ); document.write( "Try Another Example:(Very Simple1):243/45 rem is not 3 isn't it?\r
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