document.write( "Question 798212: A normal distribution has a mean of 50 and a standard deviation of 4.
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document.write( "Determine the value below which 95 percent of the observations will occur. (Round z value to 2 decimal places. Round your answer to 2 decimal places.) \n" );
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Algebra.Com's Answer #482083 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A normal distribution has a mean of 50 and a standard deviation of 4.\r \n" ); document.write( "\n" ); document.write( "Determine the value below which 95 percent of the observations will occur. \n" ); document.write( "---- \n" ); document.write( "Find the z-value with a left-tail of 0.95. \n" ); document.write( "invNorm(0.95) = 1.65 \n" ); document.write( "----- \n" ); document.write( "To find the corresponding x-value use x = z*s+u \n" ); document.write( "x = 1.65*4+50 = 56.58 \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |