document.write( "Question 798212: A normal distribution has a mean of 50 and a standard deviation of 4.
\n" ); document.write( "
\n" ); document.write( "Determine the value below which 95 percent of the observations will occur. (Round z value to 2 decimal places. Round your answer to 2 decimal places.)
\n" ); document.write( "

Algebra.Com's Answer #482083 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A normal distribution has a mean of 50 and a standard deviation of 4.\r
\n" ); document.write( "\n" ); document.write( "Determine the value below which 95 percent of the observations will occur.
\n" ); document.write( "----
\n" ); document.write( "Find the z-value with a left-tail of 0.95.
\n" ); document.write( "invNorm(0.95) = 1.65
\n" ); document.write( "-----
\n" ); document.write( "To find the corresponding x-value use x = z*s+u
\n" ); document.write( "x = 1.65*4+50 = 56.58
\n" ); document.write( "===========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===========
\n" ); document.write( "
\n" );