document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8724>Question 8724</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the center of a circle with the equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2-4x%2B6y%2B1=0 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2-4x%2B6y%2B1=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4820 by </B><A HREF=/tutors/aboutme.mpl?userid=FSAN85><B>FSAN85(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FSAN85><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OKay, this is what to do<BR>\n" );
document.write( "first rearrange the equation:<BR>\n" );
document.write( "x^2 - 4x + y^2 + 6y +1 = 0<BR>\n" );
document.write( "take the 1 to ther side<BR>\n" );
document.write( "x^2 - 4x + y^2 + 6y = -1<BR>\n" );
document.write( "now expand ur equation<BR>\n" );
document.write( "(x^2 - 4x +4) + (y^2 + 6y +9) = -1 + 4 + 9 <BR>\n" );
document.write( "break down<BR>\n" );
document.write( "(x - 2)^2 + (y + 3)^2 = 12<BR>\n" );
document.write( "Take the radical form of all the parts<BR>\n" );
document.write( "(x-2) + (y+3) = (square root)12 <BR>\n" );
document.write( "set the x ans ys to 0, that will give u ur center which turn out to be:<BR>\n" );
document.write( "A circle with a center at ( 2 , -3 ) with a radius 3.46 (squareroot of 12) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );