document.write( "Question 797963: A chemist needs 2 liters of an 18% acid solution. He has two solutions, A and B, to mix together to form the solution. Acid solution A is 10% acid and acid solution B is 15% acid. Can the chemist form the needed 18% acid solution? (Verify by calculation.) If the chemist locates a 20% acid solution, how much would have to be mixed with the 10% solution to obtain the needed 2-liter 18% solution? \n" ); document.write( "
Algebra.Com's Answer #481997 by josgarithmetic(39618)\"\" \"About 
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Let u = amount of 10% acid
\n" ); document.write( "Let v = amount of 20% acid\r
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\n" ); document.write( "\n" ); document.write( "\"%2810u%2B20v%29%2F2=18\" and \"u%2Bv=2\"
\n" ); document.write( "Solve for u and v.\r
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\n" ); document.write( "If you try the same or similar analysis for a target value of 18%, but using only the 10% and 15% acid solutions, you will obtain answers for u and v which do not make sense.
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