document.write( "Question 797886: Solve algebraically cos^2 x = sin x to find solutions in the domain 0<= x < 2 pi \n" ); document.write( "
Algebra.Com's Answer #481975 by lwsshak3(11628)\"\" \"About 
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Solve algebraically cos^2 x = sin x to find solutions in the domain 0<= x < 2 pi
\n" ); document.write( "cos^2 x = sin x
\n" ); document.write( "1-sin^2 x=sin x
\n" ); document.write( "sin^2 x+sin x-1=0
\n" ); document.write( "solve for sin x by quadratic formula:
\n" ); document.write( "\"sin+x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=1, b=1, c=-1
\n" ); document.write( "sin x=-1.618 (reject, -1 < sin x < 1)
\n" ); document.write( "or
\n" ); document.write( "sin x=0.618
\n" ); document.write( "x≈0.6661\r
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