document.write( "Question 797801: A train leaves town at 7:00am traveling south at 30mph. At 10:00 that morning, a second train leaves from the same location (on a parallel track) traveling 40 mph. At what time will it overtake the slower? You don't have to solve the problem for me. I just need help setting this up. \n" ); document.write( "
Algebra.Com's Answer #481944 by stanbon(75887)\"\" \"About 
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A train leaves town at 7:00am traveling south at 30mph. At 10:00 that morning, a second train leaves from the same location (on a parallel track) traveling 40 mph. At what time will it overtake the slower? You don't have to solve the problem for me.
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\n" ); document.write( "Early train DATA:
\n" ); document.write( "rate = 30 mph ; time = x hrs ; distance = 30x miles
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\n" ); document.write( "Later train DATA:
\n" ); document.write( "rate = 40 mph ; time = x-3 hrs ; distance = 40(x-3) miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "30x = 40(x-3)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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