document.write( "Question 797693: The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width, what are the dimensions?\r
\n" ); document.write( "\n" ); document.write( "L=102/2W-15
\n" ); document.write( "

Algebra.Com's Answer #481935 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
L length, W width.
\n" ); document.write( "L=-15+2W\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2L%2B2W=2%282W%2B15%29%2B2W=102\"
\n" ); document.write( "\"4W%2B30%2B2W=102\"
\n" ); document.write( "\"6W%2B30=102\"
\n" ); document.write( "\"6W=102-30\"
\n" ); document.write( "\"6W=72\"
\n" ); document.write( "\"W=6\"
\n" ); document.write( ".
\n" ); document.write( "and L....?
\n" ); document.write( "
\n" );