document.write( "Question 797693: The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width, what are the dimensions?\r
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document.write( "L=102/2W-15 \n" );
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Algebra.Com's Answer #481935 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! L length, W width. \n" ); document.write( "L=-15+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and L....? \n" ); document.write( " |