document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=797721>Question 797721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solved 5 sqrt root3 minus 3 div by sqrt root 3 minus 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481914 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (5sqrt(3)-3)/(sqrt(3)-1) * (sqrt(3)+1)/(sqrt(3)+1) Rationalize the denominator.<BR>\n" );
document.write( "=((5sqrt(3)-3)*(sqrt(3)+1))/(3-1)<BR>\n" );
document.write( "=(2sqrt(3)+12)/2<BR>\n" );
document.write( "=sqrt(3)+6<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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