document.write( "Question 797707: A merchant has 4 pounds of mixed nuts that cost $40. He wants to add peanuts that cost $1.70 per pound and cashews that cost $4.30 per pound to obtain 60 pounds of a mixture that costs $2.20 per pound. How many pounds of peanuts are needed? \n" ); document.write( "

Algebra.Com's Answer #481887 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+p+\"$ = pounds of peanuts needed
\n" ); document.write( "Let $\"+c+\"$ = pounds of cashews needed
\n" ); document.write( " $\"+4%2A40+=+160+\"$ = cost of mixed nuts in mixture
\n" ); document.write( " $\"+60%2A2.2+=+132+\"$ = cost of the mixture
\n" ); document.write( " $\"+60+-+4+=+56+\"$ pounds of peanuts and
\n" ); document.write( "cashews in mixture
\n" ); document.write( "-----------------
\n" ); document.write( "(1) $\"+p+%2B+c+=+56+\"$
\n" ); document.write( "(2) $\"++160+%2B+1.7p+%2B+4.3c+=+132+\"$
\n" ); document.write( "------------------------------
\n" ); document.write( "(2) $\"+1.7p+%2B+4.3c+=+-28+\"$
\n" ); document.write( "I think there is something wrong with the data.
\n" ); document.write( "The cost of the mixed nuts is $160 and they
\n" ); document.write( "want the final mixture to cost $132 which is not
\n" ); document.write( "possible. Get a 2nd opinion, definitely, but I
\n" ); document.write( "don't see a way to solve this. \n" ); document.write( "

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