document.write( "Question 797556: A triangle has an area of 24 square meters. The base is two meters longer than the height. What is the length of the base of the triangle?
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Algebra.Com's Answer #481852 by waynest(281)\"\" \"About 
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base = h + 2
\n" ); document.write( "height = h
\n" ); document.write( "A = 1/2bh
\n" ); document.write( "(1/2)h(h + 2) = 24
\n" ); document.write( "(1/2)(h^2 + 2h) = 24
\n" ); document.write( "2(1/2)(h^2 + 2h) = 2(24)
\n" ); document.write( "h^2 + 2h = 48
\n" ); document.write( "h^2 + 2h - 48 = 48 - 48
\n" ); document.write( "h^2 + 2h - 48 = 0
\n" ); document.write( "factor:
\n" ); document.write( "(h + 8)(h - 6) = 0
\n" ); document.write( "h + 8 = 0
\n" ); document.write( "h + 8 - 8 = -8
\n" ); document.write( "h = -8\r
\n" ); document.write( "\n" ); document.write( "h - 6 = 0
\n" ); document.write( "h - 6 + 6 = 6
\n" ); document.write( "h = 6\r
\n" ); document.write( "\n" ); document.write( "you can not have a negative value so h = 6\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "(1/2)(6(6 + 2)) = 24
\n" ); document.write( "(1/2)(6(8)) = 24
\n" ); document.write( "(1/2)48 = 24
\n" ); document.write( "24 = 24\r
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