document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=797266>Question 797266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a dairy has 475 pounds of milk having a content of 2.5% butterfat how many pounds of skimmed milk(with no butterfat)must he remove to have milk with a content of 4% butterfat<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481821 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if a dairy has 475 pounds of milk having a content of 2.5% butterfat<BR>\n" );
document.write( " how many pounds of skimmed milk(with no butterfat)must he remove to have milk with a content of 4% butterfat<BR>\n" );
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document.write( "Let x = amt of skim milk removed<BR>\n" );
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document.write( ".025(475) = .04(475-x)<BR>\n" );
document.write( "11.875 = 19 - .04x<BR>\n" );
document.write( ".04x = 19 - 11.875<BR>\n" );
document.write( ".04x = 7.125<BR>\n" );
document.write( "x = 7.125/.04<BR>\n" );
document.write( "x = 178.125 lbs of skim milk removed<BR>\n" );
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