document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=797359>Question 797359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay, First off, thank you for even helping me! I truly appreciate it!Well, here's my problem.. Quadrilateral TUVW with T (-4,2) U (-2,4) V (0,2) and W(-2,-4)rotated 90 degrees counterclockwise about the origin. <BR>\n" );
document.write( "       What I don't really understand is what the Quadrilateral looks like on the graph, after the rotation, and what the coordinates are for the new rotated shape. <BR>\n" );
document.write( "Thanks a MILLION and I appreciate it very much!! <BR>\n" );
document.write( "                      Sincerely<BR>\n" );
document.write( "                         ~Maria </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481763 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "So what you have is a kite shape.  The easiest point to rotate through 90 degrees counterclockwise is the point that is on one of the axes, namely (0,2).\r<BR>\n" );
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document.write( "If you rotate (0,2) 90 degrees to the left, then you end up at (-2,0). \r<BR>\n" );
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document.write( "Next the original point (-2,4) is 2 units up and 2 units left of (0,2), so the rotation of (-2,4) is goint to be 2 units down and 2 units right of (-2,0) (which is the rotation of (0,2).  That is:  (-4,-2).\r<BR>\n" );
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document.write( "Next, the original point (-4,2) is on the horizontal line through the original point (0,2) and 4 units to the left.  So the rotation of (-4,2) has to be on a vertical line with (-2,0), the rotation of (0,2), and 4 units down.  That is:  (-2,-4)\r<BR>\n" );
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document.write( "Let me know what you get for the position of the last point.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "<font face=\"Math1\" size=\"+2\">Egw to Beta kai to Sigma</font><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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