document.write( "Question 67714: Two rectangles have the same width. The length if one is 1 foor longer than the width. The length of the other is 2 feet longer than the width. The larger rectangle has 4 more square feet than the smaller. What is the width of the rectangles? \n" ); document.write( "
Algebra.Com's Answer #48172 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x=width\r
\n" ); document.write( "\n" ); document.write( "Length of DISABLED_event_one= x+1\r
\n" ); document.write( "\n" ); document.write( "Length of other=x+2
\n" ); document.write( "Area = Length times Width\r
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\n" ); document.write( "\n" ); document.write( "Now we are told that:\r
\n" ); document.write( "\n" ); document.write( "x(x+2)=x(x+1)+4 clear parens
\n" ); document.write( "x^2+2x=x^2+x+4 subtract x^2 and x from both sides\r
\n" ); document.write( "\n" ); document.write( "x^2-x^2+2x-x=x^2-x^2+x-x+4 collect like terms\r
\n" ); document.write( "\n" ); document.write( "x=4 feet----------------width of the rectangles\r
\n" ); document.write( "\n" ); document.write( "x+1=4+1=5 feet--------- length of one
\n" ); document.write( "x+2=4+2=6 feet-----------length of the other\r
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\n" ); document.write( "\n" ); document.write( "ck\r
\n" ); document.write( "\n" ); document.write( "Area of smaller=4*5=20 sq ft\r
\n" ); document.write( "\n" ); document.write( "Area of larger=4*6=24 sq ft\r
\n" ); document.write( "\n" ); document.write( "Larger is 4 more than smaller----checks\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps ----ptaylor
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