document.write( "Question 796755: Give the amplitude, period, vertical translation, and phase shift:
\n" ); document.write( "y= 1/3tan(3x-π/3)
\n" ); document.write( "I am trying to figure out why the phase shift is π/9 to the right
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Algebra.Com's Answer #481693 by lwsshak3(11628)\"\" \"About 
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Give the amplitude, period, vertical translation, and phase shift:
\n" ); document.write( "y= 1/3tan(3x-π/3)
\n" ); document.write( "***
\n" ); document.write( "Equation for tan function:y=tan(Bx-C),period=π/B, Phase shift=C/B
\n" ); document.write( "For given tan function:
\n" ); document.write( "y=(1/3)tan(3x-π/3)
\n" ); document.write( "B=3
\n" ); document.write( "Period=π/B=π/3
\n" ); document.write( "C=π/3
\n" ); document.write( "Phase shift=C/B=(π/3)/3=π/9(to the right)
\n" ); document.write( "vertical translation=1/3
\n" ); document.write( "amplitude:(-∞,∞)
\n" ); document.write( "..
\n" ); document.write( "Why phase shift to the right?
\n" ); document.write( "rewriting function might make it more recognizable. Factor out 3.
\n" ); document.write( "y=(1/3)tan3(x-π/9)
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