document.write( "Question 797137: the length of a rectangle is thrice width. if the length is increase by 8 cm and width is increase by 2 cm, the perimeter of the new rectangle is 56 cm. find the dimension of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #481675 by mohanraj04(12)\"\" \"About 
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ans:
\n" ); document.write( " given that the length(L) of rectangle is thrice width(W)
\n" ); document.write( "
\n" ); document.write( "therefore, L=3W\r
\n" ); document.write( "\n" ); document.write( "when the length is increased by 8cm and width is increased by 2 cm, then the perimeter of the rectangle is 56cm\r
\n" ); document.write( "\n" ); document.write( "therefore, 2[(L+8)+(W+2)]=56
\n" ); document.write( " 2[(3W+8)+(W+2)]=56 [since, L=3W ]
\n" ); document.write( " 2[4W+10]=56
\n" ); document.write( " 4W+10=56/2
\n" ); document.write( " 4W+10=28
\n" ); document.write( " 4W=28-10
\n" ); document.write( " 4W=18
\n" ); document.write( " W=18/4
\n" ); document.write( " W=4.5cm\r
\n" ); document.write( "\n" ); document.write( "by L=3W
\n" ); document.write( " L=3*4.5 [ since, W=4.5cm ]
\n" ); document.write( " L=13.5cm
\n" ); document.write( "there fore the dimensions of the new rectangle are L=13.5cm & W=4.5cm
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