document.write( "Question 797059: 4x+5y=3
\n" ); document.write( "3x-2y=8
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Algebra.Com's Answer #481660 by waynest(281)\"\" \"About 
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4x + 5y = 3
\n" ); document.write( "3x - 2y = 8
\n" ); document.write( "times the first equation by 3 and the second equation by 4
\n" ); document.write( "12x + 15y = 9
\n" ); document.write( "12x - 8y = -32
\n" ); document.write( "subtract the second equation from the first giving:
\n" ); document.write( "23y = -23
\n" ); document.write( "23y/23 = -23/23
\n" ); document.write( "y = -1
\n" ); document.write( "substitute -1 for y in the first equation:
\n" ); document.write( "4x + 5(-1) = 3
\n" ); document.write( "4x - 5 = 3
\n" ); document.write( "4x - 5 + 5 = 3 + 5
\n" ); document.write( "4x = 8
\n" ); document.write( "4x/4 = 8/4
\n" ); document.write( "x = 2\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "4(2) +5(-1) = 3
\n" ); document.write( "8 - 5 = 3
\n" ); document.write( "3 = 3\r
\n" ); document.write( "\n" ); document.write( "3(2) - 2(-1) = 8
\n" ); document.write( "6 + 2 = 8
\n" ); document.write( "8 = 8
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