document.write( "Question 797059: 4x+5y=3
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document.write( "3x-2y=8
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Algebra.Com's Answer #481660 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! 4x + 5y = 3 \n" ); document.write( "3x - 2y = 8 \n" ); document.write( "times the first equation by 3 and the second equation by 4 \n" ); document.write( "12x + 15y = 9 \n" ); document.write( "12x - 8y = -32 \n" ); document.write( "subtract the second equation from the first giving: \n" ); document.write( "23y = -23 \n" ); document.write( "23y/23 = -23/23 \n" ); document.write( "y = -1 \n" ); document.write( "substitute -1 for y in the first equation: \n" ); document.write( "4x + 5(-1) = 3 \n" ); document.write( "4x - 5 = 3 \n" ); document.write( "4x - 5 + 5 = 3 + 5 \n" ); document.write( "4x = 8 \n" ); document.write( "4x/4 = 8/4 \n" ); document.write( "x = 2\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "4(2) +5(-1) = 3 \n" ); document.write( "8 - 5 = 3 \n" ); document.write( "3 = 3\r \n" ); document.write( "\n" ); document.write( "3(2) - 2(-1) = 8 \n" ); document.write( "6 + 2 = 8 \n" ); document.write( "8 = 8 \n" ); document.write( " \n" ); document.write( " |