document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=796538>Question 796538</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two men starting at a point on a circular 1-mile race track walk in opposite directions with uniform speeds and meet in 6 minutes, but if they walk in the same direction, it requires one hr for the faster walker to gain a lap. What is the rate of the slower walker? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481636 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a = speed of faster walker<BR>\n" );
document.write( "Let b = speed of the slower<BR>\n" );
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document.write( "6 min to .1 hrs<BR>\n" );
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document.write( "Write an distance equation for each statement:<BR>\n" );
document.write( "dist = time * speed\r<BR>\n" );
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document.write( "Two men starting at a point on a circular 1-mile race track walk in opposite directions with uniform speeds and meet in 6 minutes,<BR>\n" );
document.write( ".1(a + b] = 1<BR>\n" );
document.write( "multiply both sides by 10<BR>\n" );
document.write( "a + b = 10<BR>\n" );
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document.write( " but if they walk in the same direction, it requires one hr for the faster walker to gain a lap. What is the rate of the slower walker?<BR>\n" );
document.write( "1(a-b) = 1<BR>\n" );
document.write( "a - b = 1<BR>\n" );
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document.write( "Use elimination here<BR>\n" );
document.write( "a + b = 10<BR>\n" );
document.write( "a - b =  1<BR>\n" );
document.write( "--------------Addition eliminates b, find a<BR>\n" );
document.write( "2a = 11<BR>\n" );
document.write( "a = 5.5 mph is a's speed<BR>\n" );
document.write( "but they want the slow guy's speed, use the 1st equation<BR>\n" );
document.write( "5.5 + b = 10<BR>\n" );
document.write( "b = 10 - 5.5<BR>\n" );
document.write( "b = 4.5 mph is the slow guys speed<BR>\n" );
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document.write( "Check this in the 2nd equation<BR>\n" );
document.write( "5.5 - 4.5 = 1 </SPAN>\n" );
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