document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=796969>Question 796969</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mrs. Lopez is 54 and has a daughter who is six years more than a third of her age. How old is Mrs. Lopez's daughter?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481630 by </B><A HREF=/tutors/aboutme.mpl?userid=omdenman><B>omdenman(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=omdenman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The daughter is 24 years old.  To find one third of Mrs. Lopez's age you do 54/3=18. Then you add 6 more to it. 18+6=24\r<BR>\n" );
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document.write( "54/3+18<BR>\n" );
document.write( "18+6=24 </SPAN>\n" );
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