document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67700>Question 67700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle.\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48160 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2(length + width) [formula for the perimeter of a rectangle]<BR>\n" );
document.write( "34=2(2w+w) [plug-in the values and simplify]<BR>\n" );
document.write( "34/2=[2(2w+w)/2<BR>\n" );
document.write( "17=2w+w<BR>\n" );
document.write( "17=3w<BR>\n" );
document.write( "17/3=(3w)/3<BR>\n" );
document.write( "17/3=w<BR>\n" );
document.write( "Therefore, the width = 17/3 in.<BR>\n" );
document.write( "Length = 2w=2(17/3) = 34/3 = 11.333 in.<BR>\n" );
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document.write( "Check by plugging all of the values back into the original formula:<BR>\n" );
document.write( "P=2(l+w)<BR>\n" );
document.write( "34=2(2w+w)<BR>\n" );
document.write( "34=2([(2)(17/3)+(17/3)]<BR>\n" );
document.write( "34=2[34/3 + 17/3]<BR>\n" );
document.write( "34=(68/3+34/3)<BR>\n" );
document.write( "34=(102/3)<BR>\n" );
document.write( "34=34 [checks out]\r<BR>\n" );
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