document.write( "Question 796789: As i am not good at this can someone help me please and show me step by step so i can solve the other 19 questions i have thank you.\r
\n" ); document.write( "\n" ); document.write( "Determine the number and type of roots for each equation
\n" ); document.write( "2X(X+2) =-2
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Algebra.Com's Answer #481586 by josgarithmetic(39628)\"\" \"About 
You can put this solution on YOUR website!
First, divide left and right sides by 2.
\n" ); document.write( "\"X%28X%2B2%29=1\".\r
\n" ); document.write( "\n" ); document.write( "\"X%5E2%2B2X=1\"
\n" ); document.write( "\"X%5E2%2B2X-1=0\"
\n" ); document.write( "Which you may TRY to factor. .....left side expressions seems unfactorable, and graph of the left side as a function might not cross the x-axis.\r
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\n" ); document.write( "\n" ); document.write( "Discriminant? \"2%2A2-4%2A1%28-1%29=4%2B4=8\", and this is positive. I would expect two REAL roots, and that the function, \"X%5E2%2B2X-1\" DOES IN FACT cross the x-axis. TWO REAL ROOTS. \r
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\n" ); document.write( "\n" ); document.write( "Using solution to quadratic formula, they would be:
\n" ); document.write( "\"%28-2%2B8%29%2F2=3\" and \"%28-2-8%29%2F2=-5++\"
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