document.write( "Question 796841: if the perimeter of a rectangle is 52 ft and the width is 11 ft what is the length? \n" ); document.write( "
Algebra.Com's Answer #481580 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! length (L) = 11 \n" ); document.write( "width = w \n" ); document.write( "2W + 2(11) = 52 \n" ); document.write( "2w + 22 = 52 \n" ); document.write( "2w + 22 - 22 = 52 - 22 \n" ); document.write( "2w = 30 \n" ); document.write( "2w/2 = 30/2 \n" ); document.write( "w = 15\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "2(15) + 2(11) = 52 \n" ); document.write( "30 + 22 = 52 \n" ); document.write( "52 = 52 \n" ); document.write( " |