document.write( "Question 796841: if the perimeter of a rectangle is 52 ft and the width is 11 ft what is the length? \n" ); document.write( "
Algebra.Com's Answer #481580 by waynest(281)\"\" \"About 
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length (L) = 11
\n" ); document.write( "width = w
\n" ); document.write( "2W + 2(11) = 52
\n" ); document.write( "2w + 22 = 52
\n" ); document.write( "2w + 22 - 22 = 52 - 22
\n" ); document.write( "2w = 30
\n" ); document.write( "2w/2 = 30/2
\n" ); document.write( "w = 15\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "2(15) + 2(11) = 52
\n" ); document.write( "30 + 22 = 52
\n" ); document.write( "52 = 52
\n" ); document.write( "
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