document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=796781>Question 796781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the first three terms and the 100th term of sequences whose nth term is given by:<BR>\n" );
document.write( "10n-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481565 by </B><A HREF=/tutors/aboutme.mpl?userid=luke94><B>luke94(89)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=luke94><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hi there, well the first three terms (starting at 0) and 100th term is\r<BR>\n" );
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document.write( "first term: 10*0 - 1 = -1<BR>\n" );
document.write( "second term: 10*1 - 1 = 9<BR>\n" );
document.write( "third term: 10*2 - 1 = 99<BR>\n" );
document.write( "hundreth term: 10*100 - 1 = 999\r<BR>\n" );
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document.write( "just substitute whatever term you are finding as your 'n' value </SPAN>\n" );
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