document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=796435>Question 796435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: 5x+1=21<BR>\n" );
document.write( "Prove: x=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481520 by </B><A HREF=/tutors/aboutme.mpl?userid=luke94><B>luke94(89)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=luke94><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there, simple algebra skills are required remember change the side = change the sign..\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%2B1=21 ALIGN=MIDDLE  ALT=\"5x%2B1=21\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "5x = 21 - 1 (notice + becomes - and vice versa)<BR>\n" );
document.write( "5x = 20 (simplified 21-1)<BR>\n" );
document.write( "x = 20/5 (notice * becomes / and vice versa)<BR>\n" );
document.write( "x = 4 (simplified 20/5)\r<BR>\n" );
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document.write( "There is your proof that 5x +1 = 21 gives x = 4<BR>\n" );
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