document.write( "Question 67697This question is from textbook
\n" ); document.write( ": At 10:00AM a car left the service station on Route 209 heading south at 86knh. At 10:30 AM another car left the station and headed south at 80kmh. At what time were the cars 55km apart? \n" ); document.write( "
Algebra.Com's Answer #48151 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "We'll first determine how many hours it takes for the cars to be 55 km apart and then add that to 10:30 AM to get our answer\r
\n" ); document.write( "\n" ); document.write( "When the difference between the distances the two cars will have traveled equals 55 km, then we will have our answer \r
\n" ); document.write( "\n" ); document.write( "distance(d) =rate(r) times time(t) or d=rt and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let x=number of hours that the 10:30 car has driven when they are 55 km apart
\n" ); document.write( "Then x+0.5= number of hours that the 10:00 car has driven \r
\n" ); document.write( "\n" ); document.write( "distance 10:30 car will have driven=80x
\n" ); document.write( "distance 10:00 car will have driven=86(x+0.5)\r
\n" ); document.write( "\n" ); document.write( "so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "86(x+0.5)-80x=55 clear parens\r
\n" ); document.write( "\n" ); document.write( "86x+43-80x=55 subtract 43 from both sides
\n" ); document.write( "6x=12
\n" ); document.write( "x=2 hours\r
\n" ); document.write( "\n" ); document.write( "10:30 AM plus 2 hours=12:30 PM-----------------------answer we are looking for\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "86*2+43= 215km\r
\n" ); document.write( "\n" ); document.write( "80*2=160km
\n" ); document.write( "215 km -160km=55km----------ck\r
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