document.write( "Question 67697This question is from textbook
\n" );
document.write( ": At 10:00AM a car left the service station on Route 209 heading south at 86knh. At 10:30 AM another car left the station and headed south at 80kmh. At what time were the cars 55km apart? \n" );
document.write( "
Algebra.Com's Answer #48151 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "We'll first determine how many hours it takes for the cars to be 55 km apart and then add that to 10:30 AM to get our answer\r \n" ); document.write( "\n" ); document.write( "When the difference between the distances the two cars will have traveled equals 55 km, then we will have our answer \r \n" ); document.write( "\n" ); document.write( "distance(d) =rate(r) times time(t) or d=rt and t=d/r\r \n" ); document.write( "\n" ); document.write( "Let x=number of hours that the 10:30 car has driven when they are 55 km apart \n" ); document.write( "Then x+0.5= number of hours that the 10:00 car has driven \r \n" ); document.write( "\n" ); document.write( "distance 10:30 car will have driven=80x \n" ); document.write( "distance 10:00 car will have driven=86(x+0.5)\r \n" ); document.write( "\n" ); document.write( "so our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "86(x+0.5)-80x=55 clear parens\r \n" ); document.write( "\n" ); document.write( "86x+43-80x=55 subtract 43 from both sides \n" ); document.write( "6x=12 \n" ); document.write( "x=2 hours\r \n" ); document.write( "\n" ); document.write( "10:30 AM plus 2 hours=12:30 PM-----------------------answer we are looking for\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "86*2+43= 215km\r \n" ); document.write( "\n" ); document.write( "80*2=160km \n" ); document.write( "215 km -160km=55km----------ck\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |