document.write( "Question 796685: how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze \n" ); document.write( "
Algebra.Com's Answer #481469 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze \n" ); document.write( "*** \n" ); document.write( "let x=amount of 90% solution to mix \n" ); document.write( "70-x=amount of 20% solution to mix \n" ); document.write( ".. \n" ); document.write( "90%x+20%(70-x)=80%*70 \n" ); document.write( ".9x+14-.2x=56 \n" ); document.write( ".7x=42 \n" ); document.write( "x=60 \n" ); document.write( "70-x=10 \n" ); document.write( ".. \n" ); document.write( "amount of 90% solution to mix=60 gal \n" ); document.write( "amount of 20% solution to mix=10 gal \n" ); document.write( " |