document.write( "Question 796685: how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze \n" ); document.write( "
Algebra.Com's Answer #481469 by lwsshak3(11628)\"\" \"About 
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how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze
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\n" ); document.write( "let x=amount of 90% solution to mix
\n" ); document.write( "70-x=amount of 20% solution to mix
\n" ); document.write( "..
\n" ); document.write( "90%x+20%(70-x)=80%*70
\n" ); document.write( ".9x+14-.2x=56
\n" ); document.write( ".7x=42
\n" ); document.write( "x=60
\n" ); document.write( "70-x=10
\n" ); document.write( "..
\n" ); document.write( "amount of 90% solution to mix=60 gal
\n" ); document.write( "amount of 20% solution to mix=10 gal
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