document.write( "Question 796688: Today, Belle's age is four less than twice the age of her sister, Cecille. in five years, twice Belle's age will be three times Cecille age. How old are they today? \n" ); document.write( "
Algebra.Com's Answer #481466 by lwsshak3(11628)\"\" \"About 
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Today, Belle's age is four less than twice the age of her sister, Cecille. in five years, twice Belle's age will be three times Cecille age. How old are they today?
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\n" ); document.write( "Today:
\n" ); document.write( "let x=Cecille's age
\n" ); document.write( "2x-4=Belle's age
\n" ); document.write( "..
\n" ); document.write( "In 5 yrs:
\n" ); document.write( "x+5=Cecille's age
\n" ); document.write( "2x-4+5=2x+1=Belle's age
\n" ); document.write( "..
\n" ); document.write( "2(2x+1)=3(x+5)
\n" ); document.write( "4x+2=3x+15
\n" ); document.write( "x=13
\n" ); document.write( "2x-4=22
\n" ); document.write( "..
\n" ); document.write( "Today:
\n" ); document.write( "Cecille's age=13
\n" ); document.write( "Belle's age=22
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