document.write( "Question 796612: The length of a rectangle is 2 in longer than its width.
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document.write( "If the perimeter of the rectangle is 32 in, find its area. \n" );
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Algebra.Com's Answer #481449 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! length (L) = w + 2 \n" ); document.write( "width = w \n" ); document.write( "p = 2w + 2L \n" ); document.write( "2w + 2(w + 2) = 32 \n" ); document.write( "2w + 2w + 4 = 32 \n" ); document.write( "4w + 4 = 32 \n" ); document.write( "4w + 4 - 4 = 32 - 4 \n" ); document.write( "4w = 28 \n" ); document.write( "4w/4 = 28/4 \n" ); document.write( "w = 7 \n" ); document.write( "L = 7 + 2 \n" ); document.write( " = 9\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "2(7) + 2(7 + 2) = 32 \n" ); document.write( "14 + 2(9) = 32 \n" ); document.write( "14 + 18 = 32 \n" ); document.write( "32 = 32 \n" ); document.write( " |