document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=796583>Question 796583</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an angle is 20 more than three times of given angle if the two angles are supplementery? the angles are </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481448 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st angle = x<BR>\n" );
document.write( "2nd angle = 3x + 20\r<BR>\n" );
document.write( "\n" );
document.write( "x + (3x + 20) = 180<BR>\n" );
document.write( "4x + 20 = 180<BR>\n" );
document.write( "4x + 20 - 20 = 180 - 20<BR>\n" );
document.write( "4x = 160<BR>\n" );
document.write( "4x/4 = 160/4<BR>\n" );
document.write( "x = 40\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "40 + (3(40) + 20) = 180<BR>\n" );
document.write( "40 + (120 + 20) = 180<BR>\n" );
document.write( "40 + 140 = 180<BR>\n" );
document.write( "180 = 180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );