document.write( "Question 67660: ok its more like factoring... but i totally forgot how to factor. ok so heres the problem:
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document.write( "6x^2-7x+2....\r
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document.write( "and i tried it and i got something like (3x+2)(2x-3) but ya thats not right because when i used FOIL it doesnt come out to what it should be... please help?! \n" );
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Algebra.Com's Answer #48139 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 6x^2-7x+2.... \n" ); document.write( "Here's one method; it's called the AC method. \n" ); document.write( "a=6, b=-7, c=2 \n" ); document.write( "---------------- \n" ); document.write( "Find two numbers whose \n" ); document.write( "product is AC = 12 \n" ); document.write( "and whose \n" ); document.write( "sum is sum is B = -7 \n" ); document.write( "------------- \n" ); document.write( "The numbers are -3 and -4 \n" ); document.write( "--------------- \n" ); document.write( "Replace the middle term of the problem with -3x-4x to get: \n" ); document.write( "6x^2-3x-4x+2 \n" ); document.write( "---------------- \n" ); document.write( "Now factor the 1st terms and the last two terms separately to get: \n" ); document.write( "3x(2x-1)-2(2x-1) \n" ); document.write( "Then factor out the common factor to end the process: \n" ); document.write( "(2x-1)(3x-2) \n" ); document.write( "----------- \n" ); document.write( "Comment: \n" ); document.write( "This may look complicated but it beas guessing. \n" ); document.write( "---------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |