document.write( "Question 67660: ok its more like factoring... but i totally forgot how to factor. ok so heres the problem:
\n" ); document.write( "6x^2-7x+2....\r
\n" ); document.write( "\n" ); document.write( "and i tried it and i got something like (3x+2)(2x-3) but ya thats not right because when i used FOIL it doesnt come out to what it should be... please help?!
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Algebra.Com's Answer #48139 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
6x^2-7x+2....
\n" ); document.write( "Here's one method; it's called the AC method.
\n" ); document.write( "a=6, b=-7, c=2
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\n" ); document.write( "Find two numbers whose
\n" ); document.write( "product is AC = 12
\n" ); document.write( "and whose
\n" ); document.write( "sum is sum is B = -7
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\n" ); document.write( "The numbers are -3 and -4
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\n" ); document.write( "Replace the middle term of the problem with -3x-4x to get:
\n" ); document.write( "6x^2-3x-4x+2
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\n" ); document.write( "Now factor the 1st terms and the last two terms separately to get:
\n" ); document.write( "3x(2x-1)-2(2x-1)
\n" ); document.write( "Then factor out the common factor to end the process:
\n" ); document.write( "(2x-1)(3x-2)
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\n" ); document.write( "Comment:
\n" ); document.write( "This may look complicated but it beas guessing.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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