document.write( "Question 796361: 1)below 300 perfect cube the sum of the digits is a multiple of 3
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Algebra.Com's Answer #481377 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "7 cubed is more than 300, so your answer is 6 cubed or less. Two perfect cubes from this set have a sum of digits divisible by 3.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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