document.write( "Question 796258: Joyce is twice the age of her brother Pepe. Five years ago, the sum of their ages is 59. find the ages of Joyce and Pepe now. \n" ); document.write( "
Algebra.Com's Answer #481312 by Cromlix(4381)\"\" \"About 
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Joyce is twice the age of her brother Pepe
\n" ); document.write( "J = 2P
\n" ); document.write( " Five years ago, the sum of their ages was 59.
\n" ); document.write( "(J - 5) + (P - 5) = 59
\n" ); document.write( "J - 5 + P - 5 = 59
\n" ); document.write( "Replace J with 2P from
\n" ); document.write( "first equation;
\n" ); document.write( "2P - 5 + P - 5 = 59
\n" ); document.write( "Collect like terms;
\n" ); document.write( "3P = 59 + 10
\n" ); document.write( "3P = 69
\n" ); document.write( "P = 23
\n" ); document.write( "Currently:
\n" ); document.write( "Pepe is 23 years old
\n" ); document.write( "Joyce is 46 years old
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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