document.write( "Question 796258: Joyce is twice the age of her brother Pepe. Five years ago, the sum of their ages is 59. find the ages of Joyce and Pepe now. \n" ); document.write( "
Algebra.Com's Answer #481312 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Joyce is twice the age of her brother Pepe \n" ); document.write( "J = 2P \n" ); document.write( " Five years ago, the sum of their ages was 59. \n" ); document.write( "(J - 5) + (P - 5) = 59 \n" ); document.write( "J - 5 + P - 5 = 59 \n" ); document.write( "Replace J with 2P from \n" ); document.write( "first equation; \n" ); document.write( "2P - 5 + P - 5 = 59 \n" ); document.write( "Collect like terms; \n" ); document.write( "3P = 59 + 10 \n" ); document.write( "3P = 69 \n" ); document.write( "P = 23 \n" ); document.write( "Currently: \n" ); document.write( "Pepe is 23 years old \n" ); document.write( "Joyce is 46 years old \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " \n" ); document.write( " |