document.write( "Question 796210: You invested $4000 between two accounts paying 2% and 8% annual interest, respectively. If the total interest earned for the years was $260, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #481281 by lwsshak3(11628)\"\" \"About 
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You invested $4000 between two accounts paying 2% and 8% annual interest, respectively. If the total interest earned for the years was $260, how much was invested at each rate?
\n" ); document.write( "***
\n" ); document.write( "let x=amount invested at 2%
\n" ); document.write( "4000-x=amount invested at 8%
\n" ); document.write( "..
\n" ); document.write( "2%x+8%(4000-x)=260
\n" ); document.write( ".02x+320-.08x=260
\n" ); document.write( ".06x=60
\n" ); document.write( "x=1000
\n" ); document.write( "4000-x=3000
\n" ); document.write( "amount invested at 2%=$1000
\n" ); document.write( "amount invested at 8%=$3000 \n" ); document.write( "
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