document.write( "Question 796110: square folded in half results in rectangle with perimeter of 39..the original area of the square is...\r
\n" ); document.write( "\n" ); document.write( "i calculate it to be 13 x 13..which is 169..am i correct?
\n" ); document.write( "

Algebra.Com's Answer #481255 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
Yes.
\n" ); document.write( "\"x\"= length of the side of the square.
\n" ); document.write( "Folding the square in half, you get a rectangle with length \"x\" and width \"x%2F2\"
\n" ); document.write( "Its perimeter would be
\n" ); document.write( "\"2%2Ax%2B2%2A%28x%2F2%29=39\"
\n" ); document.write( "\"2x%2Bx=39\"
\n" ); document.write( "\"3x=39\"
\n" ); document.write( "\"x=39%2F3\"
\n" ); document.write( "\"x=13\"
\n" ); document.write( "The area of a square with side length \"13\" is
\n" ); document.write( "\"13%2A13=13%5E2=169\"
\n" ); document.write( "
\n" ); document.write( "
\n" );