document.write( "Question 796118: Simple logarithm problem--
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document.write( "Could someone please help me? I've got a test tomorrow and my professor did not have time to explain. I'm stuck!\r
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document.write( "log3x^2=2+log9x\r
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #481239 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! log3x^2=2+log9x \n" ); document.write( "Assume it is: \n" ); document.write( "log(3x^2) = 2 + log(9x) \n" ); document.write( "Subtract log(9x) from both sides \n" ); document.write( "log(3x^2) - log(9x) = 2 \n" ); document.write( "Subtracting logs is the same as divide so we can write this \n" ); document.write( " \n" ); document.write( "note that the 3 cancels into the 9 and x into x^2, leaving us with \n" ); document.write( " \n" ); document.write( "The anti log of both sides, (10^x) on the calc) \n" ); document.write( " \n" ); document.write( "x = 3*100 \n" ); document.write( "x = 300 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out \n" ); document.write( "Enter in your calc: log(3*300^2) = 5.431.. \n" ); document.write( "Enter: 2 + log(9*300) = 5.431.. equality reigns \n" ); document.write( " |