document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=795930>Question 795930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars pass each other traveling in opposite directions. One car is going 2.5 times as fast as the other car. At the end of 3.5 hours they are 490 apart find each cars rate.   I need some direction on this please.  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481236 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two cars pass each other traveling in opposite directions.<BR>\n" );
document.write( " One car is going 2.5 times as fast as the other car.<BR>\n" );
document.write( " At the end of 3.5 hours they are 490 apart find each cars rate.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let s = speed of the slower car<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2.5s = the speed of the faster<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The relative speed is additive,<BR>\n" );
document.write( "Write a distance equation, dist = time * speed<BR>\n" );
document.write( "3.5(s + 2.5s) = 490<BR>\n" );
document.write( "3.5s + 8.75s = 490<BR>\n" );
document.write( "12.25s = 490<BR>\n" );
document.write( "s = 490/12.25<BR>\n" );
document.write( "s = 40 mph is the speed of the slower car<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2.5(40) = 100 mph is the speed of the faster </SPAN>\n" );
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