document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=796068>Question 796068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the length of a rectangle is decreased by twice the width the result is 8cm the perimeter of the rectangle is 40cm find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481235 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length - 2w = 8<BR>\n" );
document.write( "length - 2w + 2w = 8 + 2w<BR>\n" );
document.write( "length(L) = 2w + 8<BR>\n" );
document.write( "width = w<BR>\n" );
document.write( "p = 2w + 2L\r<BR>\n" );
document.write( "\n" );
document.write( "2w + 2(2w + 8) = 40<BR>\n" );
document.write( "2w + 4w + 16 = 40<BR>\n" );
document.write( "6w + 16 - 16 = 40 -16<BR>\n" );
document.write( "6w = 24<BR>\n" );
document.write( "6w/6 = 24/6<BR>\n" );
document.write( "w = 4 cm<BR>\n" );
document.write( "length = 2(4) + 8 = 16 cm\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "2(4) + 2(2(4) + 8) = 40<BR>\n" );
document.write( "8 + 2(8 + 8) = 40<BR>\n" );
document.write( "8 + 2(16) = 40<BR>\n" );
document.write( "8 + 32 = 40<BR>\n" );
document.write( "40 = 40 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );