document.write( "Question 795943: Can someone help me solve this step by step?\r
\n" ); document.write( "\n" ); document.write( "Simplify the expression.
\n" ); document.write( "[sqrt(12)-sqrt(2)][sqrt(12)+sqrt(2)]
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Algebra.Com's Answer #481204 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
[sqrt(12)-sqrt(2)][sqrt(12)+sqrt(2)]
\n" ); document.write( "let x = sqrt(12) and y = sqrt(2), then we have
\n" ); document.write( "(x -y) * (x +y)
\n" ); document.write( "x^2 -xy +xy -y^2
\n" ); document.write( "xy terms cancel
\n" ); document.write( "x^2 -y^2
\n" ); document.write( "12 -2 = 10
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