document.write( "Question 795649: find the z scores for which 97% of the distribution's area lies between -z and z. \n" ); document.write( "
Algebra.Com's Answer #481178 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the z scores for which 97% of the distribution's \n" ); document.write( "area lies between -z and z. \n" ); document.write( "===== \n" ); document.write( "That leaves 1.00-0.97 = 0.03 in the 2 tails. \n" ); document.write( "---- \n" ); document.write( "-z is the value with a left tail of (1/2)(0.03) = 0.015 \n" ); document.write( "------ \n" ); document.write( "-z = invNorm(0.015) = -2.1701 \n" ); document.write( "Then z = 2.1701 \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================= \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |