document.write( "Question 795649: find the z scores for which 97% of the distribution's area lies between -z and z. \n" ); document.write( "
Algebra.Com's Answer #481178 by stanbon(75887)\"\" \"About 
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find the z scores for which 97% of the distribution's
\n" ); document.write( "area lies between -z and z.
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\n" ); document.write( "That leaves 1.00-0.97 = 0.03 in the 2 tails.
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\n" ); document.write( "-z is the value with a left tail of (1/2)(0.03) = 0.015
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\n" ); document.write( "-z = invNorm(0.015) = -2.1701
\n" ); document.write( "Then z = 2.1701
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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