document.write( "Question 795749: 4. The Product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the 3 integers. \n" ); document.write( "
Algebra.Com's Answer #481136 by josgarithmetic(39627) ![]() You can put this solution on YOUR website! Let n be any integer. \n" ); document.write( "The needed integers are 2n+1, 2n+3, 2n+5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify and solve for n.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I omit the steps. You might think that a quadratic equation occur, but the n^2 term will be eliminated, and you will find .... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The three integers are : \n" ); document.write( "--------------------- \n" ); document.write( "2*3+1=7 \n" ); document.write( "9 \n" ); document.write( "and \n" ); document.write( "11 \n" ); document.write( "---------------------- \n" ); document.write( " |