document.write( "Question 795635: teri begins walking east at 2mph at 1:00. Cindy leaves from the same point 30 min. later going east at 3mph. when will she catch teri?\r
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Algebra.Com's Answer #481107 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
teri begins walking east at 2mph at 1:00.
\n" ); document.write( " Cindy leaves from the same point 30 min. later going east at 3mph.
\n" ); document.write( " when will she catch teri?
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\n" ); document.write( "since we are using mph, change 30 min to .5 hrs
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\n" ); document.write( "Let t = time for C to catch T
\n" ); document.write( "then
\n" ); document.write( "(t+.5) = the travel time of T
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\n" ); document.write( "When C catches T, they will have traveled the same distance
\n" ); document.write( "Write a distance equation; dist = speed * time
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\n" ); document.write( "3t = 2(t + .5)
\n" ); document.write( "3t = 2t + 1
\n" ); document.write( "3t - 2t = 1
\n" ); document.write( "t = 1 hr for C to catch T
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\n" ); document.write( "Check this by finding the actual distance of each, should be equal
\n" ); document.write( "3(1) = 3 mi
\n" ); document.write( "2(1.5) = 3 mi \n" ); document.write( "

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