document.write( "Question 795673: The value of a certain two-digit number is eight times the sum of its digits. If the digits of the number are reversed, the result is 45 less than the original number. Find the original number.\r
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document.write( "What I tried:
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document.write( "x- one's digit t- ten's digit
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document.write( "t=8(x+t)
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document.write( "t-45= 1/8 x \n" );
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Algebra.Com's Answer #481103 by josmiceli(19441) You can put this solution on YOUR website! Let \n" ); document.write( "Let \n" ); document.write( "----------------------- \n" ); document.write( "The actual value of the number is: \n" ); document.write( " \n" ); document.write( "----------- \n" ); document.write( "given: \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "--------------------------- \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "Plug (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and, since \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "The original number was 72 \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "OK \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |